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CUDA and Instruction set architecture

Shortcuts: Differences, Similarities, Jaccard Similarity Coefficient, References.

Difference between CUDA and Instruction set architecture

CUDA vs. Instruction set architecture

CUDA is a parallel computing platform and application programming interface (API) model created by Nvidia. An instruction set architecture (ISA) is an abstract model of a computer.

Similarities between CUDA and Instruction set architecture

CUDA and Instruction set architecture have 5 things in common (in Unionpedia): Instruction set architecture, Microarchitecture, Multi-core processor, Parallel computing, SIMD.

Instruction set architecture

An instruction set architecture (ISA) is an abstract model of a computer.

CUDA and Instruction set architecture · Instruction set architecture and Instruction set architecture · See more »

Microarchitecture

In computer engineering, microarchitecture, also called computer organization and sometimes abbreviated as µarch or uarch, is the way a given instruction set architecture (ISA), is implemented in a particular processor.

CUDA and Microarchitecture · Instruction set architecture and Microarchitecture · See more »

Multi-core processor

A multi-core processor is a single computing component with two or more independent processing units called cores, which read and execute program instructions.

CUDA and Multi-core processor · Instruction set architecture and Multi-core processor · See more »

Parallel computing

Parallel computing is a type of computation in which many calculations or the execution of processes are carried out concurrently.

CUDA and Parallel computing · Instruction set architecture and Parallel computing · See more »

SIMD

Single instruction, multiple data (SIMD) is a class of parallel computers in Flynn's taxonomy.

CUDA and SIMD · Instruction set architecture and SIMD · See more »

The list above answers the following questions

CUDA and Instruction set architecture Comparison

CUDA has 102 relations, while Instruction set architecture has 145. As they have in common 5, the Jaccard index is 2.02% = 5 / (102 + 145).

References

This article shows the relationship between CUDA and Instruction set architecture. To access each article from which the information was extracted, please visit:

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