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Crystallography and Paul Peter Ewald

Shortcuts: Differences, Similarities, Jaccard Similarity Coefficient, References.

Difference between Crystallography and Paul Peter Ewald

Crystallography vs. Paul Peter Ewald

Crystallography is the experimental science of determining the arrangement of atoms in crystalline solids (see crystal structure). Paul Peter Ewald, FRS (January 23, 1888 in Berlin, Germany – August 22, 1985 in Ithaca, New York) was a German crystallographer and physicist, a pioneer of X-ray diffraction methods.

Similarities between Crystallography and Paul Peter Ewald

Crystallography and Paul Peter Ewald have 4 things in common (in Unionpedia): Mathematics, Max von Laue, Peter Debye, X-ray crystallography.

Mathematics

Mathematics (from Greek μάθημα máthēma, "knowledge, study, learning") is the study of such topics as quantity, structure, space, and change.

Crystallography and Mathematics · Mathematics and Paul Peter Ewald · See more »

Max von Laue

Max Theodor Felix von Laue (9 October 1879 – 24 April 1960) was a German physicist who won the Nobel Prize in Physics in 1914 for his discovery of the diffraction of X-rays by crystals.

Crystallography and Max von Laue · Max von Laue and Paul Peter Ewald · See more »

Peter Debye

Peter Joseph William Debye (March 24, 1884 – November 2, 1966) was a Dutch-American physicist and physical chemist, and Nobel laureate in Chemistry.

Crystallography and Peter Debye · Paul Peter Ewald and Peter Debye · See more »

X-ray crystallography

X-ray crystallography is a technique used for determining the atomic and molecular structure of a crystal, in which the crystalline atoms cause a beam of incident X-rays to diffract into many specific directions.

Crystallography and X-ray crystallography · Paul Peter Ewald and X-ray crystallography · See more »

The list above answers the following questions

Crystallography and Paul Peter Ewald Comparison

Crystallography has 151 relations, while Paul Peter Ewald has 75. As they have in common 4, the Jaccard index is 1.77% = 4 / (151 + 75).

References

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