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Alexander Schrijver and VU University Amsterdam

Shortcuts: Differences, Similarities, Jaccard Similarity Coefficient, References.

Difference between Alexander Schrijver and VU University Amsterdam

Alexander Schrijver vs. VU University Amsterdam

Alexander (Lex) Schrijver (born 4 May 1948 in Amsterdam) is a Dutch mathematician and computer scientist, a professor of discrete mathematics and optimization at the University of Amsterdam and a fellow at the Centrum Wiskunde & Informatica in Amsterdam. The Vrije Universiteit Amsterdam (abbreviated as VU, VU University Amsterdam, "Free University Amsterdam") is a university in Amsterdam, Netherlands, founded in 1880.

Similarities between Alexander Schrijver and VU University Amsterdam

Alexander Schrijver and VU University Amsterdam have 4 things in common (in Unionpedia): Amsterdam, Netherlands Organisation for Scientific Research, Spinoza Prize, University of Amsterdam.

Amsterdam

Amsterdam is the capital and most populous municipality of the Netherlands.

Alexander Schrijver and Amsterdam · Amsterdam and VU University Amsterdam · See more »

Netherlands Organisation for Scientific Research

The Netherlands Organisation for Scientific Research (NWO Dutch: Nederlandse Organisatie voor Wetenschappelijk Onderzoek) is the national research council of the Netherlands.

Alexander Schrijver and Netherlands Organisation for Scientific Research · Netherlands Organisation for Scientific Research and VU University Amsterdam · See more »

Spinoza Prize

The Spinoza Prize (Spinozapremie) is an annual award of 2.5 million Euro, to be spent on new research given by the Netherlands Organisation for Scientific Research.

Alexander Schrijver and Spinoza Prize · Spinoza Prize and VU University Amsterdam · See more »

University of Amsterdam

The University of Amsterdam (abbreviated as UvA, Universiteit van Amsterdam) is a public university located in Amsterdam, Netherlands.

Alexander Schrijver and University of Amsterdam · University of Amsterdam and VU University Amsterdam · See more »

The list above answers the following questions

Alexander Schrijver and VU University Amsterdam Comparison

Alexander Schrijver has 35 relations, while VU University Amsterdam has 171. As they have in common 4, the Jaccard index is 1.94% = 4 / (35 + 171).

References

This article shows the relationship between Alexander Schrijver and VU University Amsterdam. To access each article from which the information was extracted, please visit:

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