Logo
Unionpedia
Communication
Get it on Google Play
New! Download Unionpedia on your Androidâ„¢ device!
Download
Faster access than browser!
 

Brown–Peterson cohomology and Highly structured ring spectrum

Shortcuts: Differences, Similarities, Jaccard Similarity Coefficient, References.

Difference between Brown–Peterson cohomology and Highly structured ring spectrum

Brown–Peterson cohomology vs. Highly structured ring spectrum

In mathematics, Brown–Peterson cohomology is a generalized cohomology theory introduced by, depending on a choice of prime p. It is described in detail by. In mathematics, a highly structured ring spectrum or A_\infty-ring is an object in homotopy theory encoding a refinement of a multiplicative structure on a cohomology theory.

Similarities between Brown–Peterson cohomology and Highly structured ring spectrum

Brown–Peterson cohomology and Highly structured ring spectrum have 3 things in common (in Unionpedia): Cohomology, Spectrum (topology), Suspension (topology).

Cohomology

In mathematics, specifically in homology theory and algebraic topology, cohomology is a general term for a sequence of abelian groups associated to a topological space, often defined from a cochain complex.

Brown–Peterson cohomology and Cohomology · Cohomology and Highly structured ring spectrum · See more »

Spectrum (topology)

In algebraic topology, a branch of mathematics, a spectrum is an object representing a generalized cohomology theory.

Brown–Peterson cohomology and Spectrum (topology) · Highly structured ring spectrum and Spectrum (topology) · See more »

Suspension (topology)

In topology, the suspension SX of a topological space X is the quotient space: of the product of X with the unit interval I.

Brown–Peterson cohomology and Suspension (topology) · Highly structured ring spectrum and Suspension (topology) · See more »

The list above answers the following questions

Brown–Peterson cohomology and Highly structured ring spectrum Comparison

Brown–Peterson cohomology has 15 relations, while Highly structured ring spectrum has 35. As they have in common 3, the Jaccard index is 6.00% = 3 / (15 + 35).

References

This article shows the relationship between Brown–Peterson cohomology and Highly structured ring spectrum. To access each article from which the information was extracted, please visit:

Hey! We are on Facebook now! »